# How to switfh off combine functrion in sparse?

 Classic List Threaded
5 messages
Reply | Threaded
Open this post in threaded view
|
Report Content as Inappropriate

## How to switfh off combine functrion in sparse?

 How to switfh off combine functrion  in sparse? I need to ingore new value if in data is duplicat row/col. Somthing like this : sparse(I,J,V,m,n,+=0) but this dont work.Paul
Reply | Threaded
Open this post in threaded view
|
Report Content as Inappropriate

## Re: How to switfh off combine functrion in sparse?

 try sparse(I,J,V,m,n,(a,b) ->a)On Friday, August 12, 2016 at 5:06:29 PM UTC+2, [hidden email] wrote:How to switfh off combine functrion  in sparse? I need to ingore new value if in data is duplicat row/col. Somthing like this : sparse(I,J,V,m,n,+=0) but this dont work.Paul
Reply | Threaded
Open this post in threaded view
|
Report Content as Inappropriate

## Re: How to switfh off combine functrion in sparse?

 ThX, PaulW dniu piątek, 12 sierpnia 2016 18:28:26 UTC+2 użytkownik Kristoffer Carlsson napisał:try sparse(I,J,V,m,n,(a,b) ->a)On Friday, August 12, 2016 at 5:06:29 PM UTC+2, [hidden email] wrote:How to switfh off combine functrion  in sparse? I need to ingore new value if in data is duplicat row/col. Somthing like this : sparse(I,J,V,m,n,+=0) but this dont work.Paul
Reply | Threaded
Open this post in threaded view
|
Report Content as Inappropriate

## Re: How to switfh off combine functrion in sparse?

 Why "/" and "div" not work ? julia> I 4-element Array{Int64,1}:  1  1  2  3 julia> J 4-element Array{Int64,1}:  1  1  2  3 julia> V 4-element Array{Int64,1}:  2  5  1  1 julia> sparse(I,J,V,3,3,*) 3x3 sparse matrix with 3 Int64 entries:         [1, 1]  =  10         [2, 2]  =  1         [3, 3]  =  1 julia> sparse(I,J,V,3,3,+) 3x3 sparse matrix with 3 Int64 entries:         [1, 1]  =  7         [2, 2]  =  1         [3, 3]  =  1 julia> sparse(I,J,V,3,3,/) ERROR: InexactError()  in convert at int.jl:209 julia> sparse(I,J,V,3,3,div) 3x3 sparse matrix with 3 Int64 entries:         [1, 1]  =  0         [2, 2]  =  1         [3, 3]  =  1
Reply | Threaded
Open this post in threaded view
|
Report Content as Inappropriate

## Re: How to switfh off combine functrion in sparse?

 In reply to this post by programistawpf Why "/" not work ? julia> I 4-element Array{Int64,1}:  1  1  2  3 julia> J 4-element Array{Int64,1}:  1  1  2  3 julia> V 4-element Array{Int64,1}:  2  5  1  1 julia> sparse(I,J,V,3,3,*) 3x3 sparse matrix with 3 Int64 entries:         [1, 1]  =  10         [2, 2]  =  1         [3, 3]  =  1 julia> sparse(I,J,V,3,3,+) 3x3 sparse matrix with 3 Int64 entries:         [1, 1]  =  7         [2, 2]  =  1         [3, 3]  =  1 julia> sparse(I,J,V,3,3,/) ERROR: InexactError()  in convert at int.jl:209 julia> sparse(I,J,V,3,3,div) 3x3 sparse matrix with 3 Int64 entries:         [1, 1]  =  0         [2, 2]  =  1         [3, 3]  =  1
Loading...