Do we have a decomposition syntax or macro that simplifies thisa = x.ab = x.bc = x.c...
On Wed, 2016-11-16 at 14:02, FANG Colin <[hidden email]> wrote:
> Macro seems to have answered this in a different thread....
lol: Yes that package contains "macros" but my name is Mauro :-)
> On Wednesday, November 16, 2016 at 1:01:32 PM UTC, FANG Colin wrote:
>> Do we have a decomposition syntax or macro that simplifies this
>> a = x.a
>> b = x.b
>> c = x.c